Find the equation of normal at point t of the curve $(x = t^{2})$ , $(y = 2 t + 1)$

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Solution

we have,
$x = t^{2}, y = 2 t + 1$
$\frac{d x}{d t} = 2 t, \frac{d y}{d t} = 2$
Dividing ,
$\frac{d x}{d y} = t$
$\frac{d x}{d y} = m (s l o p e)$
The equation of the normal will be
$y = t x + c$

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