Question

Find the equation of parabola, of the focus is at (a,0) and the vertex is at (a',0)

Answer 1

General equation of the parabola whose vertex are (h,k)and open downward is (x−h)^2=−4a(y−k) [Here h=a,k=0]
(X-a)^2=-4a(y-0)
(X-a)^2=-4ay so,
X^2-2xa-a^2+4ay=0