Find the equation of perpendicular bisector of the line joining the points $(2, - 3)$ and $(- 1, 5)$ .

6 x - 6 y + 13 = 0

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6 x - 16 y + 13 = 0

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x - 16 y + 13 = 0

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Solution

The correct option is B $6 x - 16 y + 13 = 0$
$m = (\frac{2 - 1}{2}, \frac{- 3 + 5}{2}) = (\frac{1}{2}, 1)$
$M_{A B} = \frac{5 + 3}{- 1 - 2} = \frac{8}{- 3} = - 8 / 3$
slope of perpendicular bisector $= 3 / 8$
$\frac{y - 1}{x - 1 / 2} = \frac{3}{8}$
$8 y - 8 = 3 x - 3 / 2$
$3 x - 8 y + 8 - 3 / 2 = 0$
$6 x - 16 y + 13 = 0$

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