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Byju's Answer
Standard XI
Mathematics
Pair of lines
find the equa...
Question
find the equation of plane passing through the line of intersection of the planes x+y+z=6 and 2x+3y=4z-5=0 and the point(1,1,1).
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Solution
The
given
equation
of
the
planes
are
:
x
+
y
+
z
-
6
=
0
.
.
.
.
1
and
2
x
+
3
y
+
4
z
-
5
=
0
.
.
.
.
2
Now
,
equation
of
the
plane
passing
through
the
line
of
intersection
of
the
planes
1
and
2
is
given
by
:
x
+
y
+
z
-
6
+
λ
2
x
+
3
y
+
4
z
-
5
=
0
⇒
1
+
2
λ
x
+
1
+
3
λ
y
+
1
+
4
λ
z
+
-
6
-
5
λ
=
0
.
.
.
.
3
Since
3
passes
through
1
,
1
,
1
,
then
it
must
satisfy
it
.
Put
x
=
y
=
z
=
1
in
3
,
we
get
1
+
2
λ
+
1
+
3
λ
+
1
+
4
λ
-
6
-
5
λ
=
0
⇒
λ
=
3
4
Now
,
putting
the
value
of
λ
in
3
,
we
get
10
x
+
13
y
+
16
z
-
39
=
0
This
is
the
required
equation
of
the
plane
.
Suggest Corrections
0
Similar questions
Q.
Equation of the plane passing through the intersection of the planes
x
+
y
+
z
=
6
and
2
x
+
3
y
+
4
z
+
5
=
0
and the point
(
1
,
1
,
1
)
is
Q.
Find the equation of the plane passing through the line of intersection of the planes
x
+
y
+
z
=
1
and
2
x
+
3
y
+
4
z
=
5
which is perpendicular to the plane
x
−
y
+
z
=
0
.
Q.
Find the equation of the plane which passes through the line of intersection of the planes
2
x
+
3
y
−
4
z
+
5
=
0
and
x
−
5
y
+
z
+
6
=
0
and is parallel to the line
x
+
y
−
z
+
8
=
0
=
x
−
y
−
z
+
2
.
Q.
Find the equation of the plane passing through the line of intersection of the planes
2
x
+
y
−
z
=
3
,
5
x
−
3
y
+
4
z
+
9
=
0
and parallel to the line
x
−
1
2
=
y
−
3
4
=
z
−
5
5
.
Q.
Find the equation of the plane containing the line of intersetion of the plane
x
+
y
+
z
−
6
=
0
and
2
x
+
3
y
+
4
z
−
5
=
0
and passing through
(
1
,
1
,
1
)
.
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