Find the equation of straight line making an angle of $120^{o}$ with the positive direction of the $x -$ axis measured counter clock wise & passing through the point $(0, - 2)$

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Solution

Slope of line $= t a n (120) = t a n (\frac{2 π}{3})$
$= t a n (π - \frac{π}{3}) = - t a n \frac{π}{3} = - \sqrt{3}$
Slope -point form of line $: y - y_{1} = m (x - x_{1})$
$\Rightarrow y + 2 = (- \sqrt{3}) (x) \Rightarrow y + \sqrt{3} x + 20$

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Find the equation of straight line making an angle of 120o with the positive direction of the x−axis measured counter clock wise & passing through the point (0,−2)

Slope of line =tan(120)=tan(2π3)=tan(π−π3)=−tanπ3=−√3Slope -point form of line :y−y1=m(x−x1)⇒y+2=(−√3)(x)⇒y+√3x+20

Find the equation of straight line making an angle of $120^{o}$ with the positive direction of the $x -$ axis measured counter clock wise & passing through the point $(0, - 2)$

Slope of line $= t a n (120) = t a n (\frac{2 π}{3})$
$= t a n (π - \frac{π}{3}) = - t a n \frac{π}{3} = - \sqrt{3}$
Slope -point form of line $: y - y_{1} = m (x - x_{1})$
$\Rightarrow y + 2 = (- \sqrt{3}) (x) \Rightarrow y + \sqrt{3} x + 20$