Find the equation of straight lines which pass through the intersection of the lines $x - 2 y - 5 = 0$ , $7 x + y = 50$ & divides the circle $x^{2} + y^{2} = 100$ into two equal halves

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Solution

A line can divide a circle in $2$ Equal halves only if passes through center of circle
So the required line passes through $(0, 0)$
Point of intersection of $x - 2 y = 5, 7 x + y = 50$ is $(7, 1)$
Equation of required line is $x = 7 y$

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Find the equation of straight lines which pass through the intersection of the lines x−2y−5=0, 7x+y=50 & divides the circle x2+y2=100 into two equal halves

A line can divide a circle in 2 Equal halves only if passes through center of circle So the required line passes through (0,0)Point of intersection of x−2y=5,7x+y=50 is (7,1)Equation of required line is x=7y

Find the equation of straight lines which pass through the intersection of the lines $x - 2 y - 5 = 0$ , $7 x + y = 50$ & divides the circle $x^{2} + y^{2} = 100$ into two equal halves

A line can divide a circle in $2$ Equal halves only if passes through center of circle
So the required line passes through $(0, 0)$
Point of intersection of $x - 2 y = 5, 7 x + y = 50$ is $(7, 1)$
Equation of required line is $x = 7 y$