Find the equation of tangent at $(3, 4)$ for the circle $x^{2} + y^{2} = 25$

3 x + 4 y = 25

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3 x - 4 y = 25

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3 x + 4 y + 25 = 0

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4 x - 3 y = 25

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Solution

The correct option is D $3 x + 4 y + 25 = 0$
The equation of circle is $x^{2} + y^{2} = 25$
The Point is $(3, 4)$
The equation of tangent at that point is $S_{1} = 0$
$⟹ x x_{1} + y y_{1} = 25 3 x + 4 y = 25$

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