Find the equation of tangent at (−32,22) to the ellipse
7x2+ 7y2+ 2xy + 10x − 10y + 7 = 0
2x + 22y =7
The equation of tangent to any second degree curve ax2 + 2hxy + by2 +2gx + 2fy + c= 0 is T = 0.
T is obtained by replacing x by x+x12 y by y+y12,x2 by xx1,y2 by yy, and xy by xy1+yx12.
and keeping the constant as it is we will apply the same for the given equation and point.
⇒ Equation of tangent is
⇒ −2x −22y + 7 = 0 or
2x +22y = 7