Question

Find the equation of the altitude drawn to side BC of $△$ ABC, whose vertices are A(-2,1), B(2,3) and C(4,5).

Answer 1

Let AD be the altitude drawn to side BC.

Slope of BC = $\frac{5-3}{4-2}=1$

Therefore, slope of AD = -1

Equation of AD is

$y-y_1=m(x-x_1)$

$y-1=-1(x+2)$

$y-1=-x-2$

$x+y+1=0$

Therefore, the required equation of the altitude is $x+y+1=0$.