Find the equation of the bisector planes of the angles between the planes 2x−y+2z+3=0 and 3x−2y+6z+8=0.
A
5x−y−4z−22=0
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B
23x−13y+32z+26=0
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C
19x−y−4z+26=0
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D
none of these
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Solution
The correct options are A5x−y−4z−22=0 B23x−13y+32z+26=0 Equation of the planes is 2x−4y+2z+3=0 and 3x−2y+6z+8=0 Then equation of the plane bisection the angles between them are 2x−4y+2z+3√4+16+4+9=±3x−2y+6z+8√9+4+36+64 ⇒2x−4y+2z+3√33=±3x−2y+6z+8√113 ⇒5x−y−4z−22=0 and 23x−13y+32z+26=0