Question

Find the equation of the chord of the hyperbola $25x^2-16y^2=400$ which is bisected at the point $(6,2)$.

• A. $75x-16y=418.$
• B. $75x+16y=418.$
• C. $75x-16y=-418.$
• D. $16x-75y=418.$

Answer 1

The correct option is A $75x-16y=418.$

Equation of the chord of the hyperbola whose mid-point is (6, 2) by $T=S_1$ is

$\frac{6x}{16}-\frac{2y}{25}=\frac{6^2}{16}-\frac{2^2}{25}.$

$\Rightarrow 75x-16y=418$