Find the equation of the circle concentric with the circle $x^{2} + y^{2} - 4 x + 6 y - 3 = 0$ and without touches the $Y -$ axis

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Solution

The equation of circle concentric with $x^{2} + y^{2} - 4 x + 6 y - 3 = 0$ is $x^{2} + y^{2} - 4 x + 6 y + c = 0$

The required equation of a circle is touching $y a x i s$

$⟹ f^{2} = c$

$3^{2} = c$

$c = 9$

So the required equation of circle is $x^{2} + y^{2} - 4 x + 6 y + 9 = 0$

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Similar questions

x^{2} + y^{2} - 4 x - 6 y - 3 = 0

Find the equation of the circle concentric with the circle $x^{2} + y^{2} - 4 x - 6 y - 3 = 0$ and which touches the y-axis.

Find the equation of the circle concentric with
$x^{2} + y^{2} - 4 x - 6 y - 3 = 0$
and which touches the y-axis.

x^{2} + y^{2} + 8 x + 10 y - 7 = 0

x^{2} + y^{2} - 4 x - 6 y = 0

x^{2} + y^{2} + 8 x + 10 y - 7 = 0

x^{2} + y^{2} - 4 x - 6 y = 0

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