Since, the circles are concentric.
Centre of required circle = Centre of x2 + y2 − 4x − 6y − 3 = 0
The centre of the required circle is (2, 3).
We know that if a circle with centre (h, k) touches the y-axis, then h is the radius of the circle.
Thus, the radius is 2.
∴ Equation of the circle: