Find the equation of the circle drawn on the intercept made by the line 2x+3y=6 between the coordinate axes as diameter.
A
x2+y2−5x−3y=0
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B
x2+y2−3x−2y=0
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C
x2−y2−2x−y=0
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D
None of these
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Solution
The correct option is Cx2+y2−3x−2y=0 The line 2x+3y=6 meets x and y-axes at A(3,0) and B(0,2) respectively. Taking AB as a diameter, the equation of the required circle is