Find the equation of the circle having $(a, 0)$ and $(0, b)$ as the extremities of the diameter.

Open in App

Solution

$(i f e n t e r p r i s e s (o, h) (a, o) d i a m e t e r o f a c i r c l e a r e g i v e n) T h e n, e q u a t i o n o f c i r c l e \Rightarrow (x - 0) (x - a) + (y - b) (y - 0) = 0 \Rightarrow x^{2} - a x + y^{2} - b y = 0 \Rightarrow x^{2} + y^{2} a x - b y = 0 A n s .$

Suggest Corrections

Similar questions

x - y - 2 = 0

x - y + 2 = 0

x - y = 0

x^{2} + y^{2} - 2 y - 9 = 0

x^{2} + y^{2} + 2 x + 3 y + 1 = 0

x^{2} + y^{2} + 9 x + 3 y + 2 = 0

A

B

A B

x + y = 3

A B

x^{2} + y^{2} - 2 x + 4 y - 8 = 0,

A B

Join BYJU'S Learning Program