Find the equation of the circle passing through the point $(0, 0)$ and the points where the straight line $3 x + 4 y = 12$ meets the axes of the coordinates

x^{2} + y^{2} - 4 x - 3 y = 0

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x^{2} + y^{2} - x - y = 0

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x^{2} + y^{2} - 4 x - y = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{2} + y^{2} - x - 3 y = 0

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Solution

The correct option is A $x^{2} + y^{2} - 4 x - 3 y = 0$

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Q. The equation of the circle passing through the point of intersection of the circle

x^{2} + y^{2} + 2 x + 3 y + 1 = 0,

x^{2} + y^{2} + 4 x + 3 y + 2 = 0

and through the point

(- 1, 2)

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Find the equation of the circle passing through the point (0,0) and the points where the straight line 3x+4y=12 meets the axes of the coordinates

The correct option is A x2+y2−4x−3y=0

Find the equation of the circle passing through the point $(0, 0)$ and the points where the straight line $3 x + 4 y = 12$ meets the axes of the coordinates

The correct option is A $x^{2} + y^{2} - 4 x - 3 y = 0$