Question

Find the equation of the circle passing through the point (2,3) and center at the point (2,0).

Answer 1

Point passing through circle is $(2,3)$

Center of circle is $(2,0)$

The equation of circle is $(x-h{)}^2+(y-k{)}^2=r^2$

$⟹(x-2{)}^2+(y-0{)}^2=r^2$

It passes through $(2,3)$

$⟹(2-2{)}^2+(3-0{)}^2=r^{2}r=3⟹x^2-4x+4+y^2=9x^2+y^2-4x-5=0$