wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the equation of the circle passing through the points:
(i) (5, 7), (8, 1) and (1, 3)
(ii) (1, 2), (3, −4) and (5, −6)
(iii) (5, −8), (−2, 9) and (2, 1)
(iv) (0, 0), (−2, 1) and (−3, 2)

Open in App
Solution

(i) Let the required circle be x2+y2+2gx+2fy+c=0. ...(1)
It passes through (5, 7), (8, 1) and (1, 3).

Substituting the coordinates of these points in equation (1):

74+10g+14f+c=0 ...(2)
65+16g+2f+c=0 ...(3)
10+2g+6f+c=0 ...(4)

Simplifying (2), (3) and (4):

g=-296, f=-196, c=563

Equation of the required circle:
x2+y2-29x3-19y3+563=0
3x2+y2-29x-19y+56=0


(ii) Let the required circle be x2+y2+2gx+2fy+c=0. ...(1)

It passes through (1, 2), (3, −4) and (5, −6).

Substituting the coordinates of these points in equation (1):

5+2g+4f+c=0 ...(2)
25+6g-8f+c=0 ...(3)
61+10g-12f+c=0 ...(4)

Simplifying (2), (3) and (4):
g=-11, f=-2, c=25

The equation of the required circle is x2+y2-22x-4y+25=0.


(iii) Let the required circle be x2+y2+2gx+2fy+c=0. ...(1)

It passes through (5, −8), (−2, 9) and (2, 1).

Substituting the coordinates of these points in equation (1):

89+10g-16f+c=0 ...(2)
85-4g+18f+c=0 ...(3)
5+4g+2f+c=0 ...(4)

Simplifying (2), (3) and (4):
g=58, f=24, c=-285

The equation of the required circle is x2+y2+116x+48y-285=0.

(iv) Let the required circle be x2+y2+2gx+2fy+c=0. ...(1)
It passes through (0, 0), (−2, 1) and (−3, 2).

Substituting the coordinates of these points in equation (1):

c=0 ...(2)
5-4g+2f+c=0 ...(3)
13-6g+4f+c=0 ...(4)

Simplifying (2), (3) and (4):

g=-32, f=-112, c=0

The equation of the required circle is x2+y2-3x-11y=0.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Reflection
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon