wiz-icon
MyQuestionIcon
MyQuestionIcon
7
You visited us 7 times! Enjoying our articles? Unlock Full Access!
Question

Find the equation of the circle passing through the points of intersection of the line x+3y=0 and 2x7y=0 and whose centre is the point of intersection of the lines x+y+1=0 and x2y+4=0.

Open in App
Solution

Thepointof intersectionofthelinex+3y=0and2x7y=0is(0,0)Let(h,k)bethecentreofcirclewithradiusa.thus,itsequationwillbe(xh)2+(yk)2=a2Thepointoftheintersectionofthelinex+y+1=0andx2y+4=0is(2,1)h=2,k=1Equationoftherequiredcircle=(x+2)2+(y1)2=a2(1)also,equation(1)passesthrough(0,0)(0+2)2+(01)2=a24+1=a2a=5(a>0)substitutingthevaluesfoainequation(1)(x+2)2+(y1)2=5x2+4+4x+y2+12y=5x2+4x+y22y=0Hence,Itistherequiredanswer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Terminology
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon