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Equation of Circle Whose Extremities of a Diameter Given

Find the equa...

Question

Find the equation of the circle passing :trough the origin and the points where the line 3x +4y = 12 meets the axes of coordinates.

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Solution

The line $3 x + 4 y = 12$
will meet the axis at A(0, 3) and B(4, 0)
Since the circle passes through origin and A and B
\therefore AB is a diameter
Thus the equation of circle is
$(x - 0) (x - 4) + (y - 3) (y - 0) = 0 x^{2} + y^{2} - 4 x - 3 y = 0$

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Equation of Circle Whose Extremities of a Diameter Given

Standard XII Mathematics

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