Question

Find the equation of the circle when the end points of a diameter are $A(-3,-2)$ and $B(3,5)$

Answer 1

Using diameter form,the equation of the circle having $A(-3,-2)$ and $B(3,5)$ as the end points of a diameter is

$(x-(-3))(x-3)+(y-(-2))(y-5)=0$

$\Rightarrow (x+3)(x-3)+(y+2)(y-5)=0$

$\Rightarrow x^2-3x+3x-9+y^2-5y+2y-10=0$

$\Rightarrow x^2+y^2-3y-19=0$ is the required equation of the circle.