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Question

Find the equation of the circle which passes through the center of the circlex2+y2+8x+10y7=0 ans is concentric with the circle 2x2+2y28x12y9=0.

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Solution

C1:x2+y2+8x+10y7=0

C2:x2+y24x6y9/2=0

C3:x2+y2+ax+by+c1=0

C3 is concentric with C2.

C3:x2+y24x6y+c=0

Centre of C1:(4,5)

(4)2+(5)24(4)6(5)+c=0

16+25+16+30+c=0.

c=87.

Therefore, equation of circle is

x2+y24x6y87=0.

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