Find the equation of the circle whose equation of two normals is x²+3x+6y+2xy=0 and is large enough to just contain the circle x(x-4)+y(y-3)=0.

$x^{2} + y^{2} - 6 x - 3 y - 45 = 0$

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$x^{2} + y^{2} + 6 x - 3 y - 45 = 0$

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$x^{2} + y^{2} + 6 x + 3 y - 45 = 0$

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Solution

The correct option is B
$x^{2} + y^{2} + 6 x - 3 y - 45 = 0$

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Find the equation of the circle whose equation of two normals is x2+3x+6y+2xy=0 and is large enough to just contain the circle x(x-4)+y(y-3)=0.

The correct option is B x2+y2+6x−3y−45=0

Find the equation of the circle whose equation of two normals is x²+3x+6y+2xy=0 and is large enough to just contain the circle x(x-4)+y(y-3)=0.

The correct option is B
$x^{2} + y^{2} + 6 x - 3 y - 45 = 0$