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Question

Find the equation of the circle whose two end points of the diameter are (4,2) and (1,3).

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Solution

Given the two end points of the diameter of the circle is (4,2) and (1,3).
Then the equation of the circle is
(x4)(x+1)+(y+2)(y3)=0
or, x2+y23xy10=0
or, x2+y23xy=10.

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