Find the equation of the circle with centre (0, 2) and radius 2

Open in App

Solution

The equation of a circle with centre (h, k) and radius r is given as

(x – h)² + (y – k)² = r²

It is given that centre (h, k) = (0, 2) and radius (r) = 2.

Therefore, the equation of the circle is

(x – 0)² + (y – 2)² = 2²

x² + y² + 4 – 4 y = 4

x² + y² – 4y = 0

Suggest Corrections

Similar questions

(- 2, 3)

4

Find the equation of the circle with
Centre (0,2) and radius 2

(1, 1)

\sqrt{2}

(- 3, 2)

4

Find the equation of the circle with
Centre (-a, -b) and radius $\sqrt{a^{2} - b^{2}}$

Join BYJU'S Learning Program