Find the equation of the circle with centre $(1, 1)$ and radius $\sqrt{2}$

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Solution

Here it is given that centre $(h, k) = (1, 1)$ and radius $r = \sqrt{2}$
Therefore the equation of the circle is
${(x - 1)}^{2} + {(y - 1)}^{2} = {(\sqrt{2})}^{2}$
$\Rightarrow x^{2} - 2 x + 1 + y^{2} - 2 y + 1 = 2$
$\Rightarrow x^{2} + y^{2} - 2 x - 2 y = 0$

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