Question

Find the equation of the circle with centre $(-3,2)$ and radius $5$

Answer 1

Since the centre of the circle is $(-3,2)$ and its radius

$5\therefore ,$ the equation of the circle is

${(x-(-3))}^2+{(y-2)}^2=5^2$

$\Rightarrow {(x+3)}^2+{(y-2)}^2=25$

$\Rightarrow x^2+6x+9+y^2-4y+4-25=0$

$\Rightarrow x^2+y^2+6x-4y-12=0$