GivenVertices(±5,0)−−−−−(1)sincetheverticesareofform(±a,0)−−−(2)hence,Majoraxisisalongx−axisandequationofellipseisx2a2+y2b2=1From(1)&(2)a=5alsogivencoordinateoffoci=(±4,0)weknowthatfoci=(±c,0)so,c=4Weknowthatc2=a2−b2(4)2=(5)2−(b)2b2=25−16b2=9b=√9∴b=3Hence,b=3Equationofellipseisx2a2+y2b2=1Puttingvaluex2(5)2+y2(3)2=1x225+y29=1Whichisrequiredequation.