MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Standard Equation of Parabola

Find the equa...

Question

Find the equation of the hyperbola whose foci are at (0, $\pm 6)$ and the length of whose conjugate axis is $2 \sqrt{11}$ .

Open in App

Solution

$\frac{y^{2}}{25} - \frac{x^{2}}{11} = 1$

Suggest Corrections

thumbs-up

2

Similar questions

Q. Find the equation of hyperbolas satisfying the following conditions:

F o c i

(0, \pm 6)

and length of conjugate axis

= 2 \sqrt{11}

Q. Find the equation of the hyperbola whose conjugate axis is

5

and the distance between the foci is

13

.

Q. Find the equation of the hyperbola whose foci are (

\pm

5, 0), the transverse axis is of length 8.

S_{1}

S_{2}

are the foci of the hyperbola whose transverse axis length is

4

and conjugate axis length is

6

S_{3}

S_{4}

are the foci of the conjugate hyperbola, then the area of the quadrilateral

S_{1} S_{3} S_{2} S_{4}

S_{1}

S_{2}

be the foci of the hyperbola whose length of transverse axis is

6

and length of conjugate axis is

10

S_{3}

S_{4}

are the foci of the conjugate hyperbola of the given hyperbola, then the area of the quadrilateral

S_{1} S_{2} S_{3} S_{4}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Parabola

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Standard Equation of Parabola

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon