Question

Find the equation of the line having an inclination ${60}^{\circ }$ with the positive direction of $X$axis and cut off an intercept of $4$ on the positive side of $Y$ axis.

Answer 1

The intercept is cut off on the positive side of $Y$ axis

$\therefore c=4$

Slope$=m=\tan \theta$

$m=\tan {60}^{\circ }=\sqrt{3}$

Equation of the line is $y=mx+c$

$y=\sqrt{3}\times x+4$

$\therefore$ Equation of the line is $\sqrt{3}x-y+4=0$