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Question

Find the equation of the line in vector form which passes through (1,2,3) and parallel to the vector 3^i+2^j2^k

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Solution

Given that, line is passing through (1,2,3) and parallel to vector 3^i+2^j2^k
Vector equation of line =¯r=(^i+2^j+3^k)+t(3^i+2^j2^k)
Cartesian equation is x13=y22=z32

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