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Question

Find the equation of the line parallel to the line 3x+2y=8 and passing through the point (0,1).


A

2x+3y-2=0

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B

3x+2y-2=0

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C

3x+2y-3=0

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D

3x+2y+3=0

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Solution

The correct option is B

3x+2y-2=0


We have, 3x+2y=8
2y=83xy=32x+4
Slope of the line, m=32
Since the required line is parallel to the given line
Slope of the required line =32
Equation of the line passing through (0,1) and having slope 32 is given by,
yy1=m(xx1)
y1=32(x0)
2y2+3x=0
3x+2y2=0, which is the required line.


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