Find the equation of the line parallel to the line 3x+2y=8 and passing through the point (0,1).
3x+2y-2=0
We have, 3x+2y=8
⇒2y=8−3x⇒y=−32x+4
∴ Slope of the line, m=−32
Since the required line is parallel to the given line
∴ Slope of the required line =−32
∴ Equation of the line passing through (0,1) and having slope −32 is given by,
y−y1=m(x−x1)
⇒y−1=−32(x−0)
⇒2y−2+3x=0
⇒3x+2y−2=0, which is the required line.