Find the equation of the line parallel to x-axis and passing through (3, -5).
Let the equation of the line be :y−y1=m(x−x1)Now,m=0 [∵ Parallel lines have equal slopes, the slope of x-axis is 0](x1, y1)=(3, −5)∴ y−y1=m(x−x1)y−(−5)=0 (x−3)y+5=0y=−5Hence, the equation of the required line is y = -5