Find the equation of the line parallel to y-axis and drawn through the point of intersection of the lines x - 7y + 5 = 0 and 3x + y = 0.

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Solution

Point of intersection of lines x - 7y = -5 and 3x + y = 0 obtained by solving these equations has coordinates

$∴ x = \frac{- 5}{22}$ and $y = \frac{15}{22}$

Since the required line is parallel to y-axis, so the equation of required line is

$x = \frac{- 5}{22}$

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Find the equation of the line parallel to y-axis and drawn through the point of intersection of the lines x - 7y + 5 = 0 and 3x + y = 0.

Point of intersection of lines x - 7y = -5 and 3x + y = 0 obtained by solving these equations has coordinates ∴ x=−522 and y=1522 Since the required line is parallel to y-axis, so the equation of required line is x=−522

Point of intersection of lines x - 7y = -5 and 3x + y = 0 obtained by solving these equations has coordinates

$∴ x = \frac{- 5}{22}$ and $y = \frac{15}{22}$

Since the required line is parallel to y-axis, so the equation of required line is

$x = \frac{- 5}{22}$