Find the equation of the line passing through the point (-2, 3) and having y – intercept of 5 units.

2 + 3y = 10

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- 3y = 10 + 2

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y = 5 +

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+ y = 7

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+ 2y = 1

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Solution

The correct option is C
y = 5 +

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Similar questions

(2, 3)

2

y + 2 x = 3, y + 2 x = 5

Find the equation of a line with y – intercept = 5 & passing through the point (–4, 7).

Find the equation of the line passing through the points (2, 3) and the point of intersection of the lines $4 x - 3 y = 7$ and $3 x + 4 y + 1 = 0$ .

(2, 3)

2

2 x + y = 3, 2 x + y = 5

x - y - 5 = 0

{(\frac{15}{A B})}^{2} + {(\frac{10}{A C})}^{2} = {(\frac{6}{A D})}^{2}

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