Find the equation of the line passing through the point (3,2) and parallel to the line $4 x + y = 11$ .

$4 x + y = 14$

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$x + 4 y - 10 = 0$

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$3 x + 4 y - 14 = 0$

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$3 x + y - 11 = 0$

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Solution

The correct option is A
$4 x + y = 14$

Line is passing through the point (3,2)

Line $4 x + y = 11$ can be written as $y = - 4 x + 11$

$\Rightarrow$ Slope = -4 [as y = mx + c, where m is the slope]

So, equation of the required line is $(y - 2) = (- 4) (x - 3)$ [point slope formula of line]

$y - 2 = - 4 x + 12$

$4 x + y = 14$

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Similar questions

x - y = 1

2 x - 3 y + 1 = 0

3 x + 4 y = 14

Find the equation of the line passing through the points (2, 3) and the point of intersection of the lines $4 x - 3 y = 7$ and $3 x + 4 y + 1 = 0$ .

3 x - 4 y + 2 = 0

(- 2, 3)

x + 2 y = 5

3 x + 7 y = 17

3 x + 4 y = 10

x + 2 y = 5

3 x + 7 y = 17

3 x + 4 y = 14

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