Find the equation of the line passing through the point (3,2) and parallel to the line 4x+y=11.
4x+y=14
Line is passing through the point (3,2)
Line 4x+y=11 can be written as y=−4x+11
⇒ Slope = -4 [as y = mx + c, where m is the slope]
So, equation of the required line is (y−2)=(−4)(x−3) [point slope formula of line]
y−2=−4x+12
4x+y=14