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Question

Find the equation of the line passing through the point of intersection of the lines 4 x + 7 y – 3 = 0 and 2 x – 3 y + 1 = 0 that has equal intercepts on the axes.

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Solution

The line is passing through the point of intersection of the lines,

4x+7y3=0(1)

2x3y+1=0(2)

Solve equation (1) and equation (2) for the point of intersection.

Substitute the value of y as 2x+1 3 from equation (2) to equation (1).

4x+7( 2x+1 3 )3=0 4x×3+14x+73×3 3 =0 12x+14x+79=0 26x2=0

Further simplify the above expression.

x= 2 26 = 1 13

Substitute the value of x in equation (1).

4 1 13 +7y3=0 4+91y39 13 =0 91y=35 y= 35 91 = 5 13

The point of intersection of the two lines is ( 1 13 , 5 13 ).

The formula for equation of line making an intercept of aand b on x axis and y axis respectively is given by,

x a + y b =1

For equal intercepts,

a=b x a + y a =1 x+y=a (3)

Substitute the values of x and y as 1 13 , 5 13 in equation

1 13 + 5 13 =a a= 6 13

Substitute the value of a in equation (3).

x+y= 6 13 13x+13y=6 13x+13y6=0

Thus, the equation of line passing through the intersection of the lines 4x+7y3=0 and 2x3y+1=0, making an equal intercept with the axes is 13x+13y6=0 .


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