Question

Find the equation of the line passing through the points (3, -5) and whose slope is 7/3.

• A. $7x-3y-36=0$
• B. $7x+3y-36=0$
• C. $7x-3y-24=0$
• D. $7x-3x+24=0$

Answer 1

Answer: (A)

$7x-3y-36=0$

A general equation for line having slope m is , y = mx + c , where m is slope of line .

Here m = $\frac{7}{3}$,

So, $3y=7x+3c$ or $3y=7x+C$

Now to eliminate C we will use the information that line passes through (3,-5),

$-15=7\left(3\right)+C$ which gives $c=-36$ .

So equation of line is , $7x-3y-36=0$ .