Question

Find the equation of the line perpendicular to x-axis and having intercept -2 on x-axis.

Answer 1

$\text{The slope of x-axis is 0, any line}\text{perpendicular to it will have slop}=\frac{-1}{0}\text{Also the required line is passing through the point (-2, 0)}\left(\text{because it is given it has x-intercept is -2}\right)\text{The required equation of line is}y-y_1=m(x-x_1)\text{Where}m=\frac{-1}{0},\left(x_1{y}_1\right)=\Rightarrow (-2,0)y-0=\frac{-1}{0},\{x-(-2\left)\right\}y-0=\frac{-1}{0}(x+2)-(x+2)=0x+2=0x=-2$