Find the equation of the line so that the line segment intercepted between the axes is divided by the point P(-5, 4) in the ratio 1: 2.
Let AB be the given line segment making intercepts a and b on the x-axis and y-axis respectively. Then, the equation of line AB is xa+yb=1
So, these points are A(a, 0) and B(0, b).
Now, P(-5, 4) divides AB in the ratio 1: 2.
∴(1×0+2×a)(1+2) = - 5 and
(1×b+2×0)(1+2)=4⇔a=−152 and b=12
So, the required equation of the line is x(−152)+y12=1⇔−2x15+y12=1
⇔8x−5y+60=0