Find the equation of the line that has an x intercept at $x = - 4$ and $y$ intercept at $y = 5$ .

4 y = 5 x + 20

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5 x - 4 y - 30 = 0

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4 x + 13 y + 5 = 0

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13 x + 4 y - 22 = 0

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Solution

The correct option is D $4 y = 5 x + 20$
The $x$ and $y$ intercepts are the points $(- 4, 0)$ and $(0, 5)$ .

The slope of the line is given by:
$m = \frac{(5 - 0)}{(0 - (- 4))} = \frac{5}{4}$

The point slope form of the line is

$y - 5 = \frac{5}{4} (x - 0)$

Multiply all terms by 4 and simplify

$4 y - 20 = 5 x$

$⟹ 4 y = 5 x + 20$

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