Question

Find the equation of the line that passes through the points $(3,4)$ and has x intercept at $x=-1$

Answer 1

We first find the slope $m$ of the line passing through the points $(3,4)$ and $(-1,0)$ (x-intercept).

The slope of the line is:

$m=\frac{y-y_1}{x-x_1}=\frac{4-0}{3-(-1)}=\frac{4}{4}=1$

Point-Slope Formula:

$y-y_1=m(x-x_1)$ where $m$ is the slope and $(x_1,y_1)$ is the given point.

Now substituting the values:

$y-0=1(x-(-1\left)\right)$

$\Rightarrow y=x+1$

Hence, the equation of the line is $y=x+1$.