Find the equation of the line which cuts off an intercept $4$ on the $x -$ axis and ass through the point $(2, - 3)$ .

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Solution

Cutting intercept of $4$ on x-axis
$\Rightarrow$ Line passes through $(4, 0)$ and $(2, - 3)$
$\Rightarrow$ Equation of line: $y + 3 = \frac{- 3}{2 - 4} (x - 2)$
$\Rightarrow y + 3 = \frac{3}{2} (x - 2)$
$\Rightarrow 2 y + 6 = 3 x - 6$
$\Rightarrow 2 y = 3 x - 12$ .

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Find the equation of the line which cuts off an intercept 4 on the x−axis and ass through the point (2,−3).

Cutting intercept of 4 on x-axis⇒ Line passes through (4,0) and (2,−3)⇒ Equation of line: y+3=−32−4(x−2)⇒y+3=32(x−2)⇒2y+6=3x−6⇒2y=3x−12.

Find the equation of the line which cuts off an intercept $4$ on the $x -$ axis and ass through the point $(2, - 3)$ .

Cutting intercept of $4$ on x-axis
$\Rightarrow$ Line passes through $(4, 0)$ and $(2, - 3)$
$\Rightarrow$ Equation of line: $y + 3 = \frac{- 3}{2 - 4} (x - 2)$
$\Rightarrow y + 3 = \frac{3}{2} (x - 2)$
$\Rightarrow 2 y + 6 = 3 x - 6$
$\Rightarrow 2 y = 3 x - 12$ .