The correct option is C 3x+ y = 0
Solving 2x - y + 5 = 0 and 5x + 3y - 4 = 0, we get x = - 1
and y = 3 i.e., the point of intersection of the given lines is (-1, 3).
∴ The equation of any line perpendicular to the line
x - 3y + 21 = 0 is 3x + y + k = 0......(1)
If this line (1) passes through the point (-1, 3), the required equation of the line is 3x + y = 0.