Find the equation of the line whose slope is $3$ and $y$ intercept is $- 4$

y = 2 x - 3

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y = 3 x + 4

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y = 3 x - 4

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y = \sqrt{3} x - 0

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Solution

The correct option is C $y = 3 x - 4$
Given $m = 3$ and $c = - 4$ ,
substituting values in $y = m x + c$ ,
we get $y = 3 x - 4$

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