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Question

Find the equation of the line whose slope is 43 and which passes through (-3, 4).

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Solution

Given, slope = fraction numerator negative 4 over denominator 3 end fraction

The equation passes through (-3, 4) = (x1, y1)

Substituting the values in y - y1 = m(x - x1), we get,

y - 4 = fraction numerator negative 4 over denominator 3 end fraction(x + 3)

3y - 12 = -4x - 12

4x + 3y = 0, which is the required equation.


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