Find the equation of the line whose slope is -4-3 and which passes through -3- 4-

Given, slope = The equation passes through ( 3, 4) = (x1, y1) Substituting the values in y y1 = m(x x1), we get, y 4 = (x + 3) 3y 12 = 4x 12 4x + 3y ...

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Slope of a Line

Find the equa...

Question

Find the equation of the line whose slope is $- \frac{4}{3}$ and which passes through (-3, 4).

Open in App

Solution

Given, slope = $fraction numerator negative 4 over denominator 3 end fraction$

The equation passes through (-3, 4) = (x₁, y₁)

Substituting the values in y - y₁ = m(x - x₁), we get,

y - 4 = $fraction numerator negative 4 over denominator 3 end fraction$ (x + 3)

3y - 12 = -4x - 12

4x + 3y = 0, which is the required equation.

Suggest Corrections

Similar questions

Q. Find the equation of the straight line whose slope is

\frac{2}{3}

and passing through

(5, - 4)

Q. Find the equation of line having slope

\frac{1}{3}

and passing through point

(3, 4)

Q. The equation of the line having slope

= 3

and passing through the point

(3, 4)

Q. Find the equation of the straight line whose slope is

- 4

and passing through

(1, 2)

Q. Find the equation of a straight line passing through

(- 1, 2)

and whose slope is

\frac{2}{3}

Join BYJU'S Learning Program

Find the equation of the line whose slope is −43 and which passes through (-3, 4).

Given, slope = The equation passes through (-3, 4) = (x1, y1) Substituting the values in y - y1 = m(x - x1), we get, y - 4 = (x + 3) 3y - 12 = -4x - 12 4x + 3y = 0, which is the required equation.

Find the equation of the line whose slope is $- \frac{4}{3}$ and which passes through (-3, 4).