Question

Find the equation of the normal to curve y² = 4x at the point (1, 2).

Answer 1

The equation of the given curve is.

Differentiating with respect to x, we have:

Now, the slope of the normal at point (1, 2) is

∴Equation of the normal at (1, 2) is y − 2 = −1(x − 1).

⇒ y − 2 = − x + 1

⇒ x + y − 3 = 0