Find the equation of the normal to the circle x2+y2=2x, which if parallel to the line x+2y=3.
A
x+2y=1
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B
x−2y=1
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C
2x+y=2
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D
2x−y=2
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Solution
The correct option is Ax+2y=1 Let equation of the normal be x+2y=c Since, center (1,0) of the circle lies on the normal we get 1+0=c⇒c=1 Therefore equation of the normal is x+2y=1